Given f(x)= [sqrt(x^2 +1) + x] / x and x>0
Solution is f(x) = sqrt[1 + (1/x^2)] +1
Can someone show we the way how to get there?
I did:
f(x)= [sqrt(x^2 +1) + x] / x
= sqrt(x^2 +1) /x + x/x
= sqrt(x^2 +1) /x + 1
But I stuck with the first term.
Thanks for any help