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Math Help - Quadratic and polynomial Equations help

  1. #1
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    Quadratic and polynomial Equations help

    I need to find the value of K in this soloution. I can't seem to figure it out.

    x^2+(2k+1)x+(k^2-5)=0


    Secondly, I need to factor

    x^3-x^2-12x

    First I use 3 as a factor and then I try and use synthetic division..
    3 | 1 -1 -12 0
    |___3__6 -18___
    1 2 -6 -18
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  2. #2
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    Quote Originally Posted by Matrim View Post
    I need to find the value of K in this soloution. I can't seem to figure it out.

    x^2=(2k+1)x+(k2-5)=0


    Secondly, I need to factor

    x^3-x^2-12x

    First I use 3 as a factor and then I try and use synthetic division..
    3 | 1 -1 -12 0
    |___3__6 -18___
    1 2 -6 -18

    Where are you getting stuck in the first one....

    For the factoring question, you should first factor out an x, then you'll have a quadratic and won't need synthetic division
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  3. #3
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    x^2+(2k+1)x+(k^2-5)=0

    I typed that out wrong

    i go..

    x^2+2xk+x+k^2-5=0

    We have been using the discriminant to do it, which numbers would i use?
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  4. #4
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    Quote Originally Posted by Matrim View Post
    x^2+(2k+1)x+(k^2-5)=0

    I typed that out wrong

    i go..

    x^2+2xk+x+k^2-5=0

    We have been using the discriminant to do it, which numbers would i use?

    Well if you wanna use the quadratic formula, you dont multiply it out,

    ax^2+bx+c=0

    In this case, b=(2k+1), c=k^2-5, a=1

    now use the quadratic formula
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  5. #5
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    Quote Originally Posted by artvandalay11 View Post
    Well if you wanna use the quadratic formula, you dont multiply it out,

    ax^2+bx+c=0

    In this case, b=(2k+1), c=k^2-5, a=1

    now use the quadratic formula
    Hmm, after reading that it seems so obvious. Thanks for your help!
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