Simplify: 3 log8 8^-2 + 1/4 log8 8^5 How would you go about doing that. I have tried doing it myself but I get the wrong answer.
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Originally Posted by JQ2009 Simplify: 3 log8 8^-2 + 1/4 log8 8^5 How would you go about doing that. I have tried doing it myself but I get the wrong answer. $\displaystyle 3log_8(8^{-2}) + \frac{1}{4}log_8(8^5)$ Use the following laws of logs ($\displaystyle b \neq 0,1$ and $\displaystyle a \neq 0$) $\displaystyle log_b(a^k) = k\,log_b(a)$ $\displaystyle log_b(b) = 1$ Spoiler: $\displaystyle (-2)(3)log_8(8) + \frac{1}{4}(5)log_8(8)$ $\displaystyle -6+\frac{5}{4} = -\frac{19}{4}$
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