I have the following:

$\displaystyle

(x^4 - 1)^\frac{1}{3}$

I know you can make that into a root:

$\displaystyle

\sqrt[3]{x^4 -1}$

but is there a way to expend that out, like you would expand:

$\displaystyle

(x^4 - 1)^2 = x^8 - 2x^4 + 1$

thanks