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Math Help - [SOLVED] Quadratic and Polynomial Equation Word Problem Help x_x

  1. #1
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    [SOLVED] Quadratic and Polynomial Equation Word Problem Help x_x

    The hypothenuse of a right triangle is 1m longer than twice one of the legs. The other leg of the triangle is 15m. Find the lengths of the unknown leg and hypothenuse.

    That's the question.


    I make a triangle with the hypothenuse as 2x+1, one side as 15, and the last side as X. The teacher said to use pythagoras but after I put it in A^2+B^2=C^2 I don't know what to do. Could anyone help me out.
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  2. #2
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    c = 2x + 1

    b = 15

    x = ?

    (2x + 1)^2 = 15 ^2 + x^2

    (2x + 1)(2x + 1) = 225 + x^2

    4x^2 + 4x + 1 = 225 + x^2

    4x^2-x^2 + 4x + 1 - 225 = 225 - 225 + x^2 - x^2

    3x^2 + 4x - 224 = 0
    (x-8)*(3x + 28) = 0

    x-8 = 0
    x = 8
    2x + 1 = 16 + 1 = 17
    here we go.
    This website might be useful
    Pythagorean theorem
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  3. #3
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    Thank you sir. I ended up figuring it out. I had made a mistake moving everything to one side. I wrote down 225 instead of 224.
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