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Math Help - logarithmic problems

  1. #1
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    Smile logarithmic problems

    I have been working on these problems and I must have a logic problem, could you put me in the right direction? Here is the problem and what I have done:
    If A=2, B=3, C=5 I am supposed to evaluate the following:
    ln(A^3/B^-3C^3)
    ln(A^3)-ln(B^-2)-ln(C^3)
    3lnA + 2lnB - 3lnC
    3ln(2) + 2ln(3) - 3ln(5) = -5516476183
    The back of my calc book tells me the answer is incorrect, could you let me know where I went wrong.
    Thank you!!!!!!!!!!!!!!!!!
    Keith Stevens
    Last edited by kcsteven; February 1st 2007 at 11:07 AM. Reason: INCORRECT SIZE ON A,B,AND C IN THE PROBLEM.
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  2. #2
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    Hello, Keith!

    Did you leave out part of the problem?


    If A=2,\:B=3,\: C=5, evaluate: . \ln\left(\frac{a^3}{b^{-3}c^3}\right)

    There is a difference between A and a.

    Is A somehow related to a ?
    If not, it's a truly stooopid problem . . .

    Here's another: .If P = 2 and Q = 7, evaluate x + y


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  3. #3
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    Quote Originally Posted by kcsteven View Post
    3ln(2) + 2ln(3) - 3ln(5) = -5516476183
    What??? You DID mean: -0.5516476183, yes?

    Quote Originally Posted by kcsteven View Post
    If A=2, B=3, C=5 I am supposed to evaluate the following:
    ln(A^3/B^-3C^3)
    Your problem is a slight typo in the second term:
    ln \left ( \frac{A^3}{B^{-3}C^3} \right )

    3ln(A) - (-3)ln(B) - 3ln(C) = 3ln(2) + 3ln(3) - 3ln(5) =\approx 0.546965

    -Dan
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