Hi, I've got this horrible fraction to solve for x for:
I don't know the next step to proceed to solve for x. Can anyone help me with it?
HI
The denominator is squared , hence it can take any real value of x to be positive . Note there is a negative sign .
The numerator has to be negative .
ln (x+1)<0
Since ln 1 =0 , ln 0 = infinity ,
ln of anything lesser than 1 would be negative .
hence 0<x+1<1
-1<x<0 would be the solution set .