HI

The denominator is squared , hence it can take any real value of x to be positive . Note there is a negative sign .

The numerator has to be negative .

ln (x+1)<0

Since ln 1 =0 , ln 0 = infinity ,

ln of anything lesser than 1 would be negative .

hence 0<x+1<1

-1<x<0 would be the solution set .