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Math Help - Fraction & Inequality: How to solve for x?

  1. #1
    Junior Member
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    Fraction & Inequality: How to solve for x?

    Hi, I've got this horrible fraction to solve for x for:

    -\frac{ln(x+1)}{(x+2)^2}>0

    I don't know the next step to proceed to solve for x. Can anyone help me with it?
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  2. #2
    MHF Contributor
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    Quote Originally Posted by Kataangel View Post
    Hi, I've got this horrible fraction to solve for x for:

    -\frac{ln(x+1)}{(x+2)^2}>0

    I don't know the next step to proceed to solve for x. Can anyone help me with it?
    HI

    The denominator is squared , hence it can take any real value of x to be positive . Note there is a negative sign .

    The numerator has to be negative .

    ln (x+1)<0

    Since ln 1 =0 , ln 0 = infinity ,

    ln of anything lesser than 1 would be negative .

    hence 0<x+1<1

    -1<x<0 would be the solution set .
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