Math Help - dividing polynomials

What I need to do here?
8^6*3^20+2^18*9^10
6^19

Hope you can help me
Thanks

If this is a simple problem for everybody, then there are no difficult problems.
It is simple for those who know how to solve it.
I can solve it in 3 lines only, but can you follow the solution?

[8^6 *3^20 +2^18 *9^10] / 6^19
= [2^18 *3^20 +2^18 *3^20] / 2^19 *3^19
= 2^19 *3^20 / 2^19 *3^19
= 3 --------answer.

Simple for me.

(Maybe, next time, avoid calling any Math problem "simple" so that, I, at least, can explain the solution in details.)

Maybe Ticbol had a bad day.
I would guess that dgolverk does not speak english as a first language and probably did not mean much by calling the post 'simple problem.'

8^6*3^20+2^18*9^10
6^19

8^6 can be written as (2^3)^6 or 2^18; (x^a)^b = x^(a*b)

2^18*3^20+2^18*9^10
6^19

9^10 can be written as (3^2)^10 or 3^20

2^18*3^20+2^18*3^20
6^19

2^18 +2^18 can be written as 2^19; x^a + x^a = x^(a+1)

2^19*3^20
6^19

6^19 can be written as 2^19*3^19; (a*b)^c = a^c * b^c

then you can simplify

2^19*3^20
2^19*3^19

to get 3

"2^18 +2^18 can be written as 2^19; x^a + x^a = x^(a+1)"

No.
x^a +x^a = 2(x^a), not x^(a+1).

x^(a+1) is (x^a)*x ---------***

2^18 +2^18 is equal to 2^19 because
2^18 +2^18
= 2(2^18)
= 2^(1+18)
= 2^19

Thanks for helping guys!
I wrote "simple problem" because I knew that you know how to slove that, and for you it's simple.