# Thread: Another log function problem

1. ## Another log function problem

Boy isn't this fun

Can someone please tell me if this is right or wrong?

If g(x) = bx and h(x) = logbx, would the graphs of these functions intersect if b = 1? If so, at what ordered pair?

g(x) = x and h(x) = log(x)

g(x) = x is a straight line through the Origin with a slope of 1

h(x) crosses the x-axis at (1,0) and does not intersect g(x).

log(x) = x has no solution.

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Would this be right or wrong? If it's wrong how can I answer the question. If it is partly right how can I do this problem in a way that would get me full marks? Do i need to show anything else in teh answer?

Thanks

2. Originally Posted by agent2421

g(x) = x and h(x) = log(x)
What is the base of the log?

Do you mean $g(x) = x$ and $h(x) = log_1(x)
$

3. sorry for not being clear. Basically i mean:

If g(x) = b^x and h(x) = $log_b(x)$ would the graphs of these functions intersect if b = 1? If so, at what ordered pair?

so I think your interpretation of the question is right. I think i did get it wrong so what steps do you need to take to solve a question like this?

4. Alright i think i figured out it would intersect but i'm not sure how to get an ordered pair.

if anyone knows of an online graphing calculator that uses logs it would be helpful because I'll be able to get a more concrete answer.

5. $h(x) = log_1(x) \Rightarrow x=1$

y = x and x=1 intersects at x=1 therefore the answer is $(x,y) = (1,1)$

6. Thanks man, appreciate you helping me.