# help please test tomorrow...help me review and find a easy way

• Oct 21st 2009, 01:37 PM
BeBeMala
help please test tomorrow...help me review and find a easy way
henry is fice times as old as his nephew. if the difference between their ages is 48 years what is henry's age?

three less than twice a number x is equal to 5 more than x. find the number????

(-2^-3x^-7)(2^5 x^6 y^9)=

calculate:: x^7y^6z^-5///// x^-4 y^8 z^-8

2(x^2 y)^0 +(3x^2)^0
• Oct 21st 2009, 01:58 PM
skeeter
Quote:

Originally Posted by BeBeMala
henry is fice times as old as his nephew. if the difference between their ages is 48 years what is henry's age?

h = 5n

h - n = 48

solve the system using substitution

three less than twice a number x is equal to 5 more than x. find the number????

2x - 3 = 5 + x

solve for x

(-2^-3x^-7)(2^5 x^6 y^9)=

property of exponents ... $\displaystyle \textcolor{red}{b^c \cdot b^d = b^{c+d}}$

calculate:: x^7y^6z^-5///// x^-4 y^8 z^-8

if this is supposed to be division ... $\displaystyle \textcolor{red}{\frac{b^c}{b^d} = b^{c-d}}$

2(x^2 y)^0 +(3x^2)^0

hint ... $\displaystyle \textcolor{red}{a^0 = 1}$

... good luck.
• Oct 21st 2009, 02:04 PM
BeBeMala
:confused::confused::confused::confused:thanx anyways
Quote:

Originally Posted by skeeter
... good luck.

• Oct 21st 2009, 02:49 PM
stapel
You've posted ten or more exercises with no work shown. The material covers a few weeks or months of material. If you are unable to make any start, then I'm afraid there is little we can do for you. So the helper wasn't being snarky. (Thinking)

Please reply with your work and reasoning so far, or else specify that you are needing lesson links so that you can spend a week or two in self-study. Thank you! (Wink)
• Oct 21st 2009, 03:01 PM
BeBeMala