the length of a rectangle L is 1 more than twice the width, and perimeter is 62.find the width and the width???

polynomials

(0.7x^2 + 0.2x-0.8)-(0.9x^2-1.1x-1.4)=

(3x-6)(2x+4)

4xy^2(7x^3 +3x^2y^2-9y^3)

(4x^3-3x^2+3x-4)(6x-4)

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- Oct 21st 2009, 01:32 PM #1

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- Oct 21st 2009, 02:10 PM #2

Please post each question in a separate thread with an explanantion on what is required and your attempts at solution.

$\displaystyle P = 2W+2L$

Where $\displaystyle L = 2W+1$ and $\displaystyle P = 62$

therefore $\displaystyle 62 = 2W+2(2W+1)$

$\displaystyle 62 = 2W+4W+2$

$\displaystyle 62 = 6W+2$

Can you solve it from here?

- Oct 21st 2009, 02:13 PM #3

- Oct 21st 2009, 02:46 PM #4

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- Oct 21st 2009, 02:51 PM #5

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