Results 1 to 3 of 3

Thread: Quick Solutions to Simplification (& Other Useful Hints)

  1. #1
    Junior Member
    Oct 2009
    Bloomington, IN

    Quick Solutions to Simplification (& Other Useful Hints)

    Hello, and thanks for the help in advance.

    I am currently in Calculus I and recently took an algebra diagnostic test that indicated that my algebra skills are a bit...lacking.

    I was hoping that any of the math gurus here on the forum could help me out with a few useful hints for simplifying expressions, etc. that students commonly learn in algebra classes.

    A few good examples of the type of thing I'm requesting are the sum and difference of two cubes formulas...they're simple and very useful if you know them, but if you don't they can stop you from demonstrating that you understand the calculus.

    This is a really open-ended request, so if anyone has anything they think might contribute, I'll definitely read over it. Thanks!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    May 2009
    The binomial expansion formula along with pascal's triangle will serve you better than simply the formula for cubes, but I am not good enough with latex to format either in a reasonable way.... but you should definitely look it up as pascal's triangle makes binomial expansion way easier

    Pascal's triangle - Wikipedia, the free encyclopedia

    Just the first part of that article will be useful for you as then it gets complicated

    Also, as you'll be dealing with limits and things later, the algebraic conjugate is something to be familiar with

    It's a useful way of multiplying by 1, for example

    $\displaystyle \frac{ax^2+bx+c}{d\sqrt{x}+e}=\frac{ax^2+bx+c}{d\s qrt{x}+e}\cdot \frac{d\sqrt{x}-e}{d\sqrt{x}-e}$

    $\displaystyle =\frac{(ax^2+bx+c)(d\sqrt{x}-e)}{d\sqrt{x}\cdot d\sqrt{x}+ed\sqrt{x}-ed\sqrt{x}-e^2}=\frac{(ax^2+bx+c)(d\sqrt{x}-e)}{d^2x-e^2}$

    It's really handy for eliminating roots in the denominator, which are generally undesirable

    And all we did was multiply by 1 in a "cool" way, by taking the denominator of our original fraction and changing the second term to a -, we were able to get rid of the root

    Not trying to scare you with 5 parameters by the way, a,b,c,d,e are just numbers
    Follow Math Help Forum on Facebook and Google+

  3. #3
    MHF Contributor
    Mar 2007


    For a lesson on special factoring formulas, try here.

    (Unfortunately, without being able to see the results of the diagnostic, there's no way for us to know what else you might need. Sorry!)
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Simplification and a Mixing Solutions Problem
    Posted in the Pre-Calculus Forum
    Replies: 3
    Last Post: Oct 23rd 2009, 06:37 AM
  2. Quick Help Realizing This simplification
    Posted in the Calculus Forum
    Replies: 2
    Last Post: Apr 7th 2009, 07:53 PM
  3. quick fraction simplification help
    Posted in the Algebra Forum
    Replies: 1
    Last Post: Mar 16th 2009, 06:47 PM
  4. Quick simplification help
    Posted in the Algebra Forum
    Replies: 2
    Last Post: Nov 10th 2008, 01:37 PM
  5. Replies: 3
    Last Post: Sep 13th 2005, 08:40 AM

Search Tags

/mathhelpforum @mathhelpforum