Can you confrim this to be the system?
I made the equations look all pretty using LaTeX. For further information look at
http://www.mathhelpforum.com/math-he...-tutorial.html
I'll kick this off for you.
....(1)
....(2)
Let's have a look at (1)
Aim to do the same thing with (2) and you should find a solution.
here's another way to do that (actually harder- pickslide's method is more fundamental and better):
Given and , take logarithms of both sides (to any base). log(5^x)+ log(25^y)= log(x) or xlog(25)+ ylog(25)= 0 and since [tex]log(25)= log(5^2)= 2log(5)[tex], x log(5)+ 2y log(5)= 0 and, dividing both sides by log(25), x+ 2y= 0.
Similarly, taking logarithms of both sides of , 5x log(3)+ y log(9)= 5x log(3)+ 2y log(3)= 0 so 5x+ 2y= 0. And it should be pretty obvious that x= 0, y= 0 is the only solution to that.
To see the "Latex" code for and , click on the formulas.