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Math Help - Another Problem

  1. #1
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    Another Problem

    Tickets for the acquaintance party were 80$ for a single ticket or 150$ for a pair. If 144 students attended the party and 10,980$ was collectred from ticket sales. How many pairs and how many singles attended?
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  2. #2
    MHF Contributor Amer's Avatar
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    Quote Originally Posted by reiward View Post
    Tickets for the acquaintance party were 80$ for a single ticket or 150$ for a pair. If 144 students attended the party and 10,980$ was collectred from ticket sales. How many pairs and how many singles attended?

    let p present pairs and s for single student

    2p+s =144

    80s +150p = 10980

    solve these two equation to get the value of p and s

    Edited : I fixed an error
    Last edited by Amer; October 19th 2009 at 10:15 AM.
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  3. #3
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    Hello reiward
    Quote Originally Posted by reiward View Post
    Tickets for the acquaintance party were 80$ for a single ticket or 150$ for a pair. If 144 students attended the party and 10,980$ was collectred from ticket sales. How many pairs and how many singles attended?
    Suppose x singles and y pairs attended.

    Then the total sales were $ (80x+150y); so 80x+150y=10980 (1)

    And the number attending was x+2y=144 (2)

    Can you solve these simultaneous equations?

    Grandad
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