1. ## Another Problem

Tickets for the acquaintance party were 80$for a single ticket or 150$ for a pair. If 144 students attended the party and 10,980$was collectred from ticket sales. How many pairs and how many singles attended? 2. Originally Posted by reiward Tickets for the acquaintance party were 80$ for a single ticket or 150$for a pair. If 144 students attended the party and 10,980$ was collectred from ticket sales. How many pairs and how many singles attended?

let p present pairs and s for single student

$\displaystyle 2p+s =144$

$\displaystyle 80s +150p = 10980$

solve these two equation to get the value of p and s

Edited : I fixed an error

3. Hello reiward
Originally Posted by reiward
Tickets for the acquaintance party were 80$for a single ticket or 150$ for a pair. If 144 students attended the party and 10,980$was collectred from ticket sales. How many pairs and how many singles attended? Suppose$\displaystyle x$singles and$\displaystyle y$pairs attended. Then the total sales were$$\displaystyle (80x+150y)$; so $\displaystyle 80x+150y=10980$ (1)

And the number attending was $\displaystyle x+2y=144$ (2)

Can you solve these simultaneous equations?