f(x) = 1/(2x)

g(x) = (3x-1)^1/2

I got the domains of f(x) and g(x) and f(g(x)). I even got the value of g(f(x))=3/2. My algebra falters with the problem f(g(x)):

1

---------

2((3x-1)^1/2)

I'm not sure where to start after setting it equal to 0.

edit: Sorry for being vague. I need to solve for zeros.