can someone help me out with this and tell me if it's right or wrong... if it's wrong how can i make it right.

f (x) = x^2/(x-2)^3

Work I've done:

f (-x) = (-x)^2/(-x-2)^3
= x^2/(-x-2)^3
= x^2/- (x-2)

f (-x) does not equal f(x)

I'm supposed to say if it's odd, even or neither but for some reason I think i did it wrong... can someone help me out.

2. Originally Posted by agent2421
can someone help me out with this and tell me if it's right or wrong... if it's wrong how can i make it right.

f (x) = x^2/(x-2)^3

Work I've done:

f (-x) = (-x)^2/(-x-2)^3
= x^2/(-x-2)^3
= x^2/- (x-2)

f (-x) does not equal f(x)

I'm supposed to say if it's odd, even or neither but for some reason I think i did it wrong... can someone help me out.
I don't get your last step, where did the cubic go?

$f(-x) = \frac{(-x)^2}{(-x-2)^3} = \frac{x^2}{(-1)^3(x-2)^3} = -\frac{x^2}{(x-2)^3}$

It appears $f(x) = -f(-x)$

3. Thanks

4. No. It's not odd and it's not even.

$

f(-x) = \frac{(-x)^2}{(-x-2)^3} = \frac{x^2}{(-1)^3(x-2)^3} = -\frac{x^2}{(x-2)^3}
$

$(-x-2)^3 \neq (-1)^3(x-2)^3$!

Try to do with a number. If x = 5, (-7)^3 = -3^3!