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Math Help - Math Help Please

  1. #1
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    Math Help Please

    can someone help me out with this and tell me if it's right or wrong... if it's wrong how can i make it right.

    f (x) = x^2/(x-2)^3


    Work I've done:

    f (-x) = (-x)^2/(-x-2)^3
    = x^2/(-x-2)^3
    = x^2/- (x-2)

    f (-x) does not equal f(x)


    I'm supposed to say if it's odd, even or neither but for some reason I think i did it wrong... can someone help me out.
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  2. #2
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    Quote Originally Posted by agent2421 View Post
    can someone help me out with this and tell me if it's right or wrong... if it's wrong how can i make it right.

    f (x) = x^2/(x-2)^3


    Work I've done:

    f (-x) = (-x)^2/(-x-2)^3
    = x^2/(-x-2)^3
    = x^2/- (x-2)

    f (-x) does not equal f(x)


    I'm supposed to say if it's odd, even or neither but for some reason I think i did it wrong... can someone help me out.
    I don't get your last step, where did the cubic go?

    f(-x) = \frac{(-x)^2}{(-x-2)^3} = \frac{x^2}{(-1)^3(x-2)^3} = -\frac{x^2}{(x-2)^3}

    It appears f(x) = -f(-x)
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  3. #3
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    Last edited by agent2421; October 18th 2009 at 11:04 AM.
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  4. #4
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    No. It's not odd and it's not even.

    <br /> <br />
f(-x) = \frac{(-x)^2}{(-x-2)^3} = \frac{x^2}{(-1)^3(x-2)^3} = -\frac{x^2}{(x-2)^3}<br />

    (-x-2)^3 \neq (-1)^3(x-2)^3!

    Try to do with a number. If x = 5, (-7)^3 = -3^3!
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