Yes, you did!
X = K^.25 6K^.75 (The same base so you adds the exponents)
X = 6K or X = L.
OK, so the equation is:
X = K^.25 L^.75, w = 2, r = 4
I know that:
Marginal Product of Labour/Marginal product of Kapital = w/r
So I take the derivative with regards to "l" on top and do the same with respect to "k" on bottom and get...
(3/4K^.25 L^-0.25)/(1/4K^-0.75 L^0.25) = 2/4
The 4's on bottom negate each other...and we know that the negative exponent flips to the other side of the dividing line, which gives us:
3K/L = 1/2
Cross multiply, survey says...
6K = L
Now, I know I have to plug this back into the original equation (ie. for every "L" there is 6"k")...when I do that, I get
X = K^0.25 6K^0.75
My question is where do I go from here, and did I do the math right?
Ibrox
From what you've posted, K (or k?) is "on top", so I'm not sure what you mean by "to 'k' on bottom"...? Also, you posted this to "pre-algebra", but then refer to taking derivatives (from post-algebra calculus)...?
How do X, K, L, w, r, l, and k relate? With respect to what are you differentiating? What are you differentiating? What are the necessary formulas and relations? What are you trying to accomplish?
Please be complete. Thank you!