# Equations with fractions

• Oct 18th 2009, 06:55 AM
zyx.gar
Equations with fractions
$\displaystyle \frac {x}{4} - \frac{2x-1}{x+1} = 1$

x(x+1) - 4(2x-1) = 1(4)(x+1)

x^2 + x - 8x - 4 = 4x + 4

x^2 + x - 8x - 4 - 4x - 4 = 0

x^2 - 11x - 8 = 0

From there I factorise it to get the answer, but the answer it's supposed to be is 0 , 11
I can't see how that would work out unless it's just x^2 - 11x I think there may be a problem with the fours maybe but I'm not sure.
• Oct 18th 2009, 07:09 AM
e^(i*pi)
Quote:

Originally Posted by zyx.gar
$\displaystyle \frac {x}{4} - \frac{2x-1}{x+1} = 1$

x(x+1) - 4(2x-1) = 1(4)(x+1)

x^2 + x - 8x - 4 = 4x + 4 e^(i*pi): -4*-1 = 4 not -4

x^2 + x - 8x +4 - 4x - 4 = 0

x^2 - 11x = 0

From there I factorise it to get the answer, but the answer it's supposed to be is 0 , 11
I can't see how that would work out unless it's just x^2 - 11x I think there may be a problem with the fours maybe but I'm not sure.

See the comment in red, x^2-11x=0 is the correct expression and should be easy to solve for the given solutions
• Oct 18th 2009, 09:28 AM
zyx.gar
Yeah I see what I've done there I had it all out of order on my pad. Thanks.
• Oct 18th 2009, 06:50 PM
pacman
the graph is beautiful, see

http://www4c.wolframalpha.com/Calcul...image/gif&s=28

(Bow)
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