At noon, ship A passes 9 km west of a harbour, heading due south at 8 km/h. At 11 a.m., ship B had left the harbour, sailing due south at 6 km/h. Give an expression for d, the distance between the two ships, in terms of t, the number of hours after noon.
i really dont even know how to start on this problem,.
start by making a sketch of the situation.
Originally Posted by samtheman17
let the harbor be at the origin and let t = 0 be noon
at t = 0 , ship A is at position (-9,0) and is heading south at 8 km/hr ...
its position at any time t is (-9, -8t)
at t = 0, ship B is at position (0, -6) and is heading south at 6 km/hr ...
its position at any time t is (0, -6 - 6t)
use the distance formula to find the distance between the two ships at any time t.
thank you so much, that really helped! :)