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Math Help - Ratio and Proportion

  1. #1
    Junior Member
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    Smile Ratio and Proportion

    Hello!
    This is a question about ratio and proportion, which I've tried to solve, but got the wrong answer. The correct answer is apparently 2, but I got someting like 0.0042 - and I am not sure what I did wrong.
    Therefore, I would appreciate your help

    The question is:
    a+b = 1/6

    ((a-b)^2 + ab) / ((3a^3) + (3b^3)) = ?

    Thanks!
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  2. #2
    MHF Contributor
    Joined
    Sep 2008
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    West Malaysia
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    Quote Originally Posted by Aminekhadir View Post
    Hello!
    This is a question about ratio and proportion, which I've tried to solve, but got the wrong answer. The correct answer is apparently 2, but I got someting like 0.0042 - and I am not sure what I did wrong.
    Therefore, I would appreciate your help

    The question is:
    a+b = 1/6

    ((a-b)^2 + ab) / ((3a^3) + (3b^3)) = ?

    Thanks!
    HI

    \frac{(a-b)^2+ab}{3a^3+3b^3}

     =\frac{a^2-2ab+b^2+ab}{3(a+b)(a^2-ab+b^2)}

    =\frac{a^2+b^2-ab}{3(a+b)(a^2-ab+b^2)}

    cancel off

    \frac{1}{3(a+b)}

    You should be able to take it from here .
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