So, after 3 times it is x/8+x= x/8+ 8x/8= 9x/8 and then repeats: (9x/8)/8+ (9x/8)= 9x/64+ 9x/8= 9x/64+ 72x/64= 81x/64= . And then repeats again: (81x/64)/8+ (81x/64)= 81x/512+ 81x/64= 81x/512+ 648x/512= 729x/512= . Looks to me like, after 3n "reduction times" x is multiplied by [itex](9/8)^n[/itex].

Now 1095/3= 365 so 1095= 3(365).