Factorise completely x^3-16x
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Hello Mist Originally Posted by Mist Factorise completely x^3-16x Take out a common factor, $\displaystyle x$, and then use 'difference of two squares' on what's left in the bracket; i.e. $\displaystyle a^2 - b^2 = (a+b)(a-b)$. Can you do it now? Grandad
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