# Thread: finding zeros and roots by factoring

1. ## finding zeros and roots by factoring

x^2+3x=0

and

5x^2-8x-4=0

2. Originally Posted by ashleeyy-
x^2+3x=0
$x(x+3) = 0$. This means either $x=0$ or $x+3=0$.

5x^2-8x-4=0
Because 5 is prime it must be 5 x 1 for coefficients of x^2.
Trying -2*2 for the -4 and manipulating gives

$(5x+2)(x-2)=0$

This will come naturally with practice