1. ## Rational Function

vertical asymptote: x = 1
horizontal asymptote: y = −2
y-intercept: (0, −1)

The question is to find a rational function that supports that information.
the y-intercept is is just the coordinates.

vertical asymptotes: x = −1 and x = 2
horizontal asymptote: y = 3
x-intercept: (3, 0)

Same with this one. Rational function that supports that information.

2. Originally Posted by goliath
vertical asymptote: x = 1
horizontal asymptote: y = −2
y-intercept: (0, −1)

The question is to find a rational function that supports that information.
the y-intercept is is just the coordinates.

vertical asymptotes: x = −1 and x = 2
horizontal asymptote: y = 3
x-intercept: (3, 0)

Same with this one. Rational function that supports that information.
1. $\displaystyle y = \frac{A}{x - 1} - 2$. Substitute (0, -1) to solve for A.

2. $\displaystyle y = \frac{A}{(x + 1)(x - 2)} + 3$. Substitute (3, 0) to solve for A.

Then express both over a common denominator.

3. how do i solve for A

4. Originally Posted by goliath
how do i solve for A
I have told you how in my first reply.

5. I got the first one but I can't seem to the get the second one.

I got [-12/(x+1)(x-2)] +3

6. Originally Posted by goliath
I got the first one but I can't seem to the get the second one.

I got [-12/(x+1)(x-2)] +3
Do you know how to substitute a given point into an equation?

7. Well, I said I got the first one didn't I?

8. Nevermind, I figured it out. A = -12

so it's 3(x+4)(x-3)/((x+1)(x-2))