how would i do this

y=mx+x/2m

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- Oct 14th 2009, 11:02 AMmaths noobrearranging formulae with fractions
how would i do this

y=mx+x/2m - Oct 14th 2009, 11:07 AMe^(i*pi)
- Oct 14th 2009, 11:31 AMmaths noob
ooops x

- Oct 14th 2009, 11:33 AMe^(i*pi)
Because x is in both terms it can be factored out:

$\displaystyle

y = mx + \frac{x}{2m} = x\left(m+\frac{1}{2m}\right)

$

Divide through to isolate x:

$\displaystyle x = \frac{y}{\left(m+\frac{1}{2m}\right)}$

That can be tidied up by multiplying through by $\displaystyle 2m$

$\displaystyle x = \frac{2my}{2m^2+1}$