I'm finding it difficult to solve this question
It's solving quadratic eqaution by completing the square
x^2+12x+3=0
This is what I have done so far ...
x^2+12x+3=0
x^2 +12x=-3
(x+12)^2-144=-3
(x+12)^2=141
x+12=√141
Then, I don't know what to do
I'm finding it difficult to solve this question
It's solving quadratic eqaution by completing the square
x^2+12x+3=0
This is what I have done so far ...
x^2+12x+3=0
x^2 +12x=-3
(x+12)^2-144=-3
(x+12)^2=141
x+12=√141
Then, I don't know what to do
You have the right idea. However, it should be $\displaystyle (x+6)^2$, not $\displaystyle (x+12)^2$, you always take half of the coefficient of $\displaystyle x$.
Also, when you square root your equation, you end up with two terms on the right hand side. For example $\displaystyle \sqrt{4}$ would give you 4 and -4.
You seem to be struggling with some of the basic mathematical operations, I suggest that you take some time to read through your notes/books on the subject.
Hope this helps
No.
You started off right, however you went wrong from the highlighted point above.
Because you are only considering the positive square root you are missing out a solution!
I have $\displaystyle x = 1.5 \pm\sqrt{7.25}$
You are not far off, just keep practising, and take your time, dont rush things when you are unsure about them.
Hope this helps
Go to the forum LaTex Help and have a look here: http://www.mathhelpforum.com/math-he...-tutorial.html