Results 1 to 4 of 4

Math Help - "Cans of Paint" Word Problem

  1. #1
    Junior Member
    Joined
    Oct 2009
    Posts
    38

    "Cans of Paint" Word Problem

    Hey guys, this problem has been giving me a headache for the last hour, and its the last problem I need to do before my homework is due in an hour and a half! Help!

    I have two cans of paint. Can A has 9 parts of blue paint to one part of yellow paint. Can B is 20 percent blue paint and the rest is yellow paint. How much paint should I use from each can to obtain 2 liters of paint which is half blue and half yellow.


    amount of can A= ___________________ liters
    amount of can B= ___________________ liters
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Junior Member
    Joined
    Oct 2009
    Posts
    38


    The farthest I keep getting is that A + B= 2L, but I have no idea what other equation to set up, I've tried a bunch.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Super Member
    earboth's Avatar
    Joined
    Jan 2006
    From
    Germany
    Posts
    5,830
    Thanks
    123
    Quote Originally Posted by Togechu64 View Post
    Hey guys, this problem has been giving me a headache for the last hour, and its the last problem I need to do before my homework is due in an hour and a half! Help!

    I have two cans of paint. Can A has 9 parts of blue paint to one part of yellow paint. Can B is 20 percent blue paint and the rest is yellow paint. How much paint should I use from each can to obtain 2 liters of paint which is half blue and half yellow.


    amount of can A= ___________________ liters
    amount of can B= ___________________ liters
    1. Can A: \frac9{10} blue + \frac1{10} yellow

    Can B: \frac2{10} blue + \frac8{10} yellow

    2. Let x denote the amount of cans A and y the amount of cans B. Of each color you need exactly 1 litre.

    3. Solve the system of equations for x, y:

    \left|\begin{array}{rcl} \frac{9}{10} x + \frac{2}{10} y &=& 1 {\color{blue}\bold{blue}}\\  \frac{1}{10} x + \frac{8}{10} y &=& 1 {\color{yellow}\bold{yellow}}\end{array}\right.

    Spoiler:
    I've got x = \frac67~\vee~y=\frac87
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Junior Member
    Joined
    Oct 2009
    Posts
    38
    PERFECT!!! I worked it out and got exactly the right answer, thank you so much, you're an incredible life saver! I've made sure to write down your explanation so I have a practice problem to review for the midterm, thank you very much again for all your help!!!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 3
    Last Post: October 17th 2011, 03:50 PM
  2. Replies: 2
    Last Post: August 6th 2011, 04:00 PM
  3. Replies: 2
    Last Post: April 24th 2011, 08:01 AM
  4. Replies: 1
    Last Post: October 25th 2010, 05:45 AM
  5. A "work" word problem, need help!
    Posted in the Algebra Forum
    Replies: 1
    Last Post: June 20th 2008, 02:25 AM

Search Tags


/mathhelpforum @mathhelpforum