Hey guys,

"Find a function g(x) such that fog(x) is a quadratic function"

f(x) = (1+x)^1/2 - 2

(which would be square root (1+x)) - 2

2. Originally Posted by goliath
Hey guys,

"Find a function g(x) such that fog(x) is a quadratic function"

f(x) = (1+x)^1/2 - 2

(which would be square root (1+x)) - 2
I think this would work.

$f(x)=\sqrt{1+x}-2$

Let: $g(x)=x^4-1$

$(f\circ g)(x)=\sqrt{1+(x^4-1)}-2$

$=\sqrt{x^4}-2$

$=x^2-2$

This is a second degree polynomial, so I guess the function your looking for is $g(x)=x^4-1$