Hi, can someone show me how to solve the expression x^6 - y^6?
It must be done 2 ways: A) Treating it as a different of squares and B) Treating it as a difference of cubes
I'm really confused. Thanks for help!!
Thanks for the response. And yes, I am familiar with the basic A-B formula. However I don't understand why it expands to become:
A) $\displaystyle (x-y)(x^2+xy+y^2)(x+y)(x^2-xy+y^2)$
B) $\displaystyle (x-y)(x+y)(x^4+x^2y^2+y^4)$ --> if this is a difference of squares, why is there a (x+y)?
*Answers from the back of the book
For A) I understand why would factor $\displaystyle (x-y)$ and $\displaystyle (x+y)$ but where is the $\displaystyle (x^2+xy+y^2)(x^2-xy+y^2)$ coming from?
For B) I know where the $\displaystyle (x-y)$ is coming from (difference of cubes, [a-b]) but where is the $\displaystyle (x+y)$ and $\displaystyle (x^4+x^2y^2+y^4)$ coming from? I kind of understand the trinomial part given that $\displaystyle [a^2+ab+b^2]$. But other than that, I'm pretty much lost.