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Math Help - solving equations with fractions

  1. #1
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    solving equations with fractions

    need help on solving these problems

     1/5x+27=22
    1/2x-29=-22
    3x/5+22=28
    14-2x/3=18
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  2. #2
    MHF Contributor
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    Quote Originally Posted by Haxcake View Post
    need help on solving these problems

     1/5x+27=22
    1/2x-29=-22
    3x/5+22=28
    14-2x/3=18
    If I understand what you mean, you want to solve for x in each of those 4 equations, and 1/5x is actually (1/5)x or x/5.

    So,
    x/5 +27 = 22
    Collect like terms, numbers with numbers, unknowns with unknowns,
    x/5 = 22 -27
    x/5 = -5
    Clear the fraction, multiply both sides by 5,
    x = -25 ----------------answer.

    ----------------------------------------------
    x/2 -29 = -22
    x/2 = -22 +29
    x/2 = 7
    x = 7*2
    x = 14 --------------answer.

    -------------------------------------------
    3x/5 +22 = 28
    3x/5 = 28 -22
    3x/5 = 6
    3x = 6*5
    3x = 30
    To isolate x, or so that x will be alone,
    Divide both sides by 3,
    x = 30/3
    x = 10 -------------------answer.

    ------------------------------------------------
    14 -2x/3 = 18
    -2x/3 = 18 -14
    -2x/3 = 4
    Clear the fraction, multiply both sides by 3,
    -2x = 12
    So that x will be alone, divide both sides by -2,
    x = 12 / -2
    x = -6 -------------answer.

    ------------------------------------------
    Note:
    When you solve for x, or any unknown, in an equation, just do anything to isolate the x, or any unknown. Get the x, or any unknown, be alone by itself at one side of the equation.
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  3. #3
    Junior Member
    Joined
    Jan 2007
    Posts
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    Quote Originally Posted by Haxcake View Post
    need help on solving these problems

     1/5x+27=22
    1/2x-29=-22
    3x/5+22=28
    14-2x/3=18
    use brackets

    if you mean

    {1/(5x) } + 27 = 22

    then {1/(5x) } = 22 -27

    {1/(5x) } = -5

    so that x = 1/(-5*5)

    or x = -1 / 25
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