1. ## Percentage Problem.

Here is a question that I am having some serious difficulty on solving..

There are 75 more women than men enrolled in Linden College. If there are n men enrolled, then in terms of n, what percent of those enrolled are men?

I thought that the answer would be:

$\frac{n}{n+75}$ because n is the number of men and n+75 is the total number of students so, this would give me the percent of men enrolled.. but apparently that answer is wrong. Can someone please help me figure out the true answer?

2. Originally Posted by gs.sh11
Here is a question that I am having some serious difficulty on solving..

There are 75 more women than men enrolled in Linden College. If there are n men enrolled, then in terms of n, what percent of those enrolled are men?

I thought that the answer would be:

$\frac{n}{n+75}$ because n is the number of men and n+75 is the total number of students so, this would give me the percent of men enrolled.. but apparently that answer is wrong. Can someone please help me figure out the true answer?
If n is the number of men, and there are 75 more women than men, then the number of women is $n+75$, and the total number of students is $n+n+75 = 2n+75$ hence the answer is

$\frac{n}{2n+75}$

Your answer, $\frac{n}{n+75}$, is the men:women ratio.

3. Ahhhh I see! Thankyou very much!

4. $\frac{men}{men+women}$

$\frac{n}{n+n+75}$

$\frac{n}{2n+75}$