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Math Help - Partial Fraction

  1. #1
    Junior Member
    Joined
    Apr 2008
    Posts
    45

    Partial Fraction

    so I have

    x^2 / (x-1)(x-2)

    The answer is 1 - 1/(x-1) + 4/(x-2).

    Where did the 1 come from. I did the whole solving for A and B thing and got the same answer without the 1.

    Thanks.
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  2. #2
    Member
    Joined
    May 2009
    From
    New Delhi
    Posts
    153
     \frac {x^2}{(x-1)(x-2)}=\frac {x^2}{x^2-3x+2}= 1+\frac{3x-2}{x^2-3x+2}=1+\frac{3x-2}{(x-1)(x-2)}
    now resolve  \frac{3x-2}{(x-1)(x-2)} into partial fraction
     \frac{3x-2}{(x-1)(x-2)}=\frac{- 1}{(x-1)} + \frac{4}{(x-2)}
    therefore\quad \frac {x^2}{(x-1)(x-2)}=1-\frac{ 1}{(x-1)} + \frac{4}{(x-2)}
    Last edited by ramiee2010; October 13th 2009 at 05:17 AM.
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