How do I isolate x here?

48.99 = 36.34(1+x)^2 + ([(1+x)^2 - 1]/x)

I get to:

(1+x)^2 = (48.99x + 1)/(36.34x + 1)

But I can't simplify my equation further.

Also, x > 0. I know x = 0.1355 but I can't get to it algebraically.

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- Oct 12th 2009, 02:26 PMVolcanicrainIsolating a variable (hard)
How do I isolate x here?

48.99 = 36.34(1+x)^2 + ([(1+x)^2 - 1]/x)

I get to:

(1+x)^2 = (48.99x + 1)/(36.34x + 1)

But I can't simplify my equation further.

Also, x > 0. I know x = 0.1355 but I can't get to it algebraically. - Oct 12th 2009, 02:46 PMRaoh
$\displaystyle \frac{(1+x)^{2}(36.34x+1)-(48.99x+1)}{36.34x+1}=0$ $\displaystyle \Leftrightarrow 36.34 x^3+73.68 x^2-10.65 x=0$ solve for $\displaystyle x$ ,you'll get $\displaystyle x=0.13549$ for$\displaystyle x> 0$

- Oct 12th 2009, 02:48 PMBarthayn
$\displaystyle 48.99 = 36.34(1+x)^2 + ([(1+x)^2 - 1]/x)$

$\displaystyle 48.99 = 36.34(x^2+2x+1) + ([(1+x)^2 - 1]/x)$

$\displaystyle 48.99 = 36.34x^2 + 72.68x + 36.34 + (x^2 + 2x / x)$

$\displaystyle 48.99x = 36.34x^2 + 72.68x + 36.34 + x^2 + 2x $

$\displaystyle 48.99x = 37.34x^2 + 74.68x + 36.34$

$\displaystyle -25.69x = 37.34x^2 + 36.34$

$\displaystyle -25.69x = 6.11x + 36.34$

$\displaystyle -31.8x = 36.34$

$\displaystyle x = -1.14$

Does this help? - Oct 12th 2009, 02:53 PMVolcanicrain
- Oct 12th 2009, 02:56 PMRaoh
- Oct 12th 2009, 08:58 PMWilmer