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Math Help - Prove that in a triangle a^2+b^2+c^2<=9R^2

  1. #1
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    Prove that in a triangle a^2+b^2+c^2<=9R^2

    Prove that in a triangle a^2+b^2+c^2\le 9R^2 where a,\, b\, c are the lengths of the sides and R is the radius of the circumcircle.
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  2. #2
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    Drwa the diagram first and then solve the LHS first.

    there will be 3 different triangles and take 2 at a time and since they will be congruent by SAS condition(side angle side) replace the a by the R by solving it further.....try it !!!!!!!!!!1
    Last edited by CaptainBlack; October 11th 2009 at 01:24 PM.
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