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Math Help - solving for y

  1. #1
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    solving for y

    solve:

    (11/4 y^1/4) - (3/2y^-3/4) = 0
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  2. #2
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    Quote Originally Posted by samtheman17 View Post
    solve:

    (11/4 y^1/4) - (3/2y^-3/4) = 0
    if you mean ...

    \frac{11}{4} y^{\frac{1}{4}} - \frac{3}{2} y^{-\frac{3}{4}} = 0

    then start by multiplying every term by y^{\frac{3}{4}}
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  3. #3
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    okay..........

    so far i have

    (22/4 y ^3/16) - (6/2y ^ -9/16)

    now i make the others have the same denominator so.....

    (22/4 y ^ 3/16) - (12/4y ^ -9/16) ......

    now im not sure how to subtract exponents
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  4. #4
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    Quote Originally Posted by samtheman17 View Post
    okay..........

    so far i have

    (22/4 y ^3/16) - (6/2y ^ -9/16)

    now i make the others have the same denominator so.....

    (22/4 y ^ 3/16) - (12/4y ^ -9/16) ......

    now im not sure how to subtract exponents
    you do not multiply the exponents.

    note the following ...

    y^{\frac{3}{4}} \cdot y^{\frac{1}{4}} = y^{\frac{3}{4} + \frac{1}{4}} = y

    y^{\frac{3}{4}} \cdot y^{-\frac{3}{4}} = y^{\frac{3}{4} - \frac{3}{4}} = y^0 = 1
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  5. #5
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    ohh okay, so

    (11/4 y) - (3/2) = 0

    then solve for y and get 6/11

    thanks you !
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