Thread: need help

I have two problems that I'm not sure if I did them right.

The first one is:

Solve the equation: sqrt z = -1

my answer:

(sqrt z)^2 = -1^2

z= 1

The second one is:

Solve the equation: sqrt 2a = 2

my answer:

(sqrt 2a)^2 = 2^2

2a = 4

Please help me understand this eqations.

Thank you in advance.

Solve the equation: sqrt z = -1

my answer:

(sqrt z)^2 = -1^2

z= 1

Excellent!

Solve the equation: sqrt 2a = 2

my answer:

(sqrt 2a)^2 = 2^2

2a = 4 Just complete the solution by dividing both sides by 2.

When one side of an eq is a SQRT, squaring both sides is the way to solve.
You're doing great.

Originally Posted by ctelady

Solve the equation: sqrt z = -1

my answer:

(sqrt z)^2 = -1^2

z= 1

Excellent!

Solve the equation: sqrt 2a = 2

my answer:

(sqrt 2a)^2 = 2^2

2a = 4 Just complete the solution by dividing both sides by 2.

When one side of an eq is a SQRT, squaring both sides is the way to solve.
You're doing great.

So, for the second equation my answer is going to be a=2 ?

So, for the second equation my answer is going to be a=2 ?
Exactly right. Plug it back into the problem to check it.

Thank you for the help.