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Math Help - need help

  1. #1
    Newbie
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    Oct 2005
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    need help

    I have two problems that I'm not sure if I did them right.

    The first one is:

    Solve the equation: sqrt z = -1

    my answer:

    (sqrt z)^2 = -1^2

    z= 1

    The second one is:

    Solve the equation: sqrt 2a = 2

    my answer:

    (sqrt 2a)^2 = 2^2

    2a = 4

    Please help me understand this eqations.

    Thank you in advance.
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  2. #2
    Junior Member
    Joined
    Oct 2005
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    Solve the equation: sqrt z = -1

    my answer:

    (sqrt z)^2 = -1^2

    z= 1

    Excellent!

    Solve the equation: sqrt 2a = 2

    my answer:

    (sqrt 2a)^2 = 2^2

    2a = 4 Just complete the solution by dividing both sides by 2.

    When one side of an eq is a SQRT, squaring both sides is the way to solve.
    You're doing great.
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  3. #3
    Newbie
    Joined
    Oct 2005
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    Quote Originally Posted by ctelady
    Solve the equation: sqrt z = -1

    my answer:

    (sqrt z)^2 = -1^2

    z= 1

    Excellent!

    Solve the equation: sqrt 2a = 2

    my answer:

    (sqrt 2a)^2 = 2^2

    2a = 4 Just complete the solution by dividing both sides by 2.

    When one side of an eq is a SQRT, squaring both sides is the way to solve.
    You're doing great.
    So, for the second equation my answer is going to be a=2 ?
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  4. #4
    Junior Member
    Joined
    Oct 2005
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    So, for the second equation my answer is going to be a=2 ?
    Exactly right. Plug it back into the problem to check it.
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  5. #5
    Newbie
    Joined
    Oct 2005
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    8

    Talking

    Thank you for the help.
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