Hi,
im really not sure how to approach this problem.
Factor Fully the following expression...
abx^3 + (a-2b-ab)x^2 + (2b-a-2)x + 2
the answer i know is (x-1)(ax-2)(bx+1)
really not sure how to get the answer
thanks in advance
Hi,
im really not sure how to approach this problem.
Factor Fully the following expression...
abx^3 + (a-2b-ab)x^2 + (2b-a-2)x + 2
the answer i know is (x-1)(ax-2)(bx+1)
really not sure how to get the answer
thanks in advance
A slightly different way:
If x= 1, so x- 1 is a factor. Dividing by x- 1 gives a quotient of . Solving with the quadratic formula gives . Taking the "+", that is so is a factor. Taking the "-", that is so is the third factor. Putting those together, we have which does not have the "ab" times a. It is really
.