# Thread: Finding X (Quite easy..)

1. ## Finding X (Quite easy..)

(3y-1)-1/2(2y+6/8-y-5/3)

2. Originally Posted by Julian.Ignacio
(3y-1)-1/2(2y+6/8-y-5/3)
Well, Julian. I give up. Where is x?

3. Originally Posted by masters
Well, Julian. I give up. Where is x?
Sorry for misusing some words .
It's just a monomial calculation, I know the answer, but I forgot how to develop it.

But I wasn't sarcastic, it IS easy. note: /=fraction (I don't know html coding sorry).

4. Originally Posted by Julian.Ignacio
(3y-1)-1/2(2y+6/8-y-5/3)
Originally Posted by Julian.Ignacio
Sorry for misusing some words .
It's just a monomial calculation, I know the answer, but I forgot how to develop it.

But I wasn't sarcastic, it IS easy. note: /=fraction (I don't know html coding sorry).
Your title said to 'find x' and your expression is in 'y'.

I'm having trouble untangling your expression. Is it one of these:

(1) $3y-1-\frac{1}{2}\left(\frac{2y+6}{8-y}-\frac{5}{3}\right)$

(2) $3y-1-\frac{1}{2}\left(2y+\frac{6}{8}-y-\frac{5}{3}\right)$

(3) $3y-1-\frac{1}{2}\left(\frac{2y+6}{8}-\frac{y-5}{3}\right)$

Or something else entirely?

5. Originally Posted by Julian.Ignacio
It's just a monomial calculation, I know the answer.... it IS easy.
You ask to find x, but you seem to need to simplify an expression in y...?

You say it's easy, but you show no progress on it...?

I'm confused.

6. The third one. Thank you

7. Originally Posted by stapel
You ask to find x, but you seem to need to simplify an expression in y...?

You say it's easy, but you show no progress on it...?

I'm confused.
What I meant about easy is that it's basic algebra (11 year old swiss here sorry).

8. Originally Posted by masters
Your title said to 'find x' and your expression is in 'y'.

I'm having trouble untangling your expression. Is it one of these:

(1) $3y-1-\frac{1}{2}\left(\frac{2y+6}{8-y}-\frac{5}{3}\right)$

(2) $3y-1-\frac{1}{2}\left(2y+\frac{6}{8}-y-\frac{5}{3}\right)$

(3) $3y-1-\frac{1}{2}\left(\frac{2y+6}{8}-\frac{y-5}{3}\right)$

Or something else entirely?
Originally Posted by Julian.Ignacio
The third one. Thank you

(3) $3y-1-\frac{1}{2}\left(\frac{2y+6}{8}-\frac{y-5}{3}\right)$

Simplify what's in parenthesis. The common denominator will be 24.

$3y-1-\frac{1}{2}\left(\frac{3(2y+6)}{24}-\frac{8(y-5)}{24}\right)$

$3y-1-\frac{1}{2}\left(\frac{6y+18}{24}-\frac{8y-40}{24}\right)$

$3y-1-\frac{1}{2}\left(\frac{6y+18-8y+40}{24}\right)$

$3y-1-\frac{1}{2}\left(\frac{-2y+58}{24}\right)$

$3y-1+\frac{2y-58}{48}$

Put everything over a denominator of 48.

$\frac{144y-48+2y-58}{48}$

$\frac{146y-106}{48}$

$\boxed{\frac{73y}{24}-\frac{53}{24}}$

And by the way....Go Federer!

9. Hahaha pardon for the backled english and thanks for the answer AND Fed xDDD hahahah.