I have to write an equation y=mx+b, I know the slope (m) and a point that the line passes through (3, 2) Slope is 1/2
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Originally Posted by md56 I have to write an equation y=mx+b, I know the slope (m) and a point that the line passes through (3, 2) Slope is 1/2 start with the point-slope form ... $\displaystyle y - y_1 = m(x - x_1)$ then convert to slope-intercept form
Originally Posted by md56 I have to write an equation y=mx+b, I know the slope (m) and a point that the line passes through (3, 2) Slope is 1/2 $\displaystyle y = \frac{x}{2} + b$. Now substitute (3, 2) and solve for b.
Why did I not think of that? Thanks!
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