Thread: How do you find slope-intercept

I have to write an equation y=mx+b, I know the slope (m) and a point that the line passes through (3, 2)

Slope is 1/2

Originally Posted by md56

I have to write an equation y=mx+b, I know the slope (m) and a point that the line passes through (3, 2)

Slope is 1/2

start with the point-slope form ...

$\displaystyle y - y_1 = m(x - x_1)$

then convert to slope-intercept form

Originally Posted by md56

I have to write an equation y=mx+b, I know the slope (m) and a point that the line passes through (3, 2)

Slope is 1/2

$\displaystyle y = \frac{x}{2} + b$.

Now substitute (3, 2) and solve for b.

Why did I not think of that? Thanks!