Algebra

**CantcountWontcount** · October 6th 2009, 10:43 AM

Subtract (3/2)a-b/3+c from b/2-4a-3c

Anyone?

**ramiee2010** · October 6th 2009, 11:17 AM

$\frac{b}{2}-4a-3c-(\frac{3}{2}a-\frac{b}{3}+c)$

$\frac{b}{2}-4a-3c-\frac{3}{2}a+\frac{b}{3}-c$

$\frac{b}{2}+\frac{b}{3}-4a-\frac{3}{2}a-3c-c$

$\frac{5}{6}b-\frac {11}{2}a-4c$

**janvdl** · October 6th 2009, 11:21 AM

Originally Posted by CantcountWontcount

Subtract (3/2)a-b/3+c from b/2-4a-3c

Anyone?

$\left( -4a + \frac{1}{2}b - 3c \right) - \left( \frac{3}{2}a - \frac{1}{3}b + c \right)$

$= \left( -4 - \frac{3}{2} \right) a + \left( \frac{1}{2} + \frac{1}{3} \right)b + (-3 - 1)c$

Can you continue?

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