how to solve equation

**JQ2009** · October 6th 2009, 08:09 AM

3/(x-1) - 2/(x+1) = 2/x(^2) -1

Could someone please tell me how you solve that?

**masters** · October 6th 2009, 08:21 AM

Originally Posted by JQ2009

3/(x-1) - 2/(x+1) = 2/x(^2) -1

Could someone please tell me how you solve that?

Hi JQ2009,

$\frac{3}{x-1}-\frac{2}{x+1}=\frac{2}{x^2-1}$

$\frac{3}{x-1}-\frac{2}{x+1}=\frac{2}{(x-1)(x+1)}$

Now, multiply each term by (x-1)(x+1) and continue from there.

**JQ2009** · October 6th 2009, 10:54 AM

Thanks but I am still confused.

I know that leaves you with 2 on the right hand side but what happens to the left?

**masters** · October 6th 2009, 11:32 AM

Originally Posted by masters

Hi JQ2009,

$\frac{3}{x-1}-\frac{2}{x+1}=\frac{2}{x^2-1}$

$\frac{3}{x-1}-\frac{2}{x+1}=\frac{2}{(x-1)(x+1)}$

Now, multiply each term by (x-1)(x+1) and continue from there.

Originally Posted by JQ2009

Thanks but I am still confused.

I know that leaves you with 2 on the right hand side but what happens to the left?

$(x-1)(x+1)\left(\frac{3}{(x-1}\right)-(x-1)(x+1)\left(\frac{2}{x+1}\right)=(x-1)(x+1)\left(\frac{2}{(x-1)(x+1)}\right)$

$3(x+1)-2(x-1)=2$

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