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Math Help - how to solve equation

  1. #1
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    how to solve equation

    3/(x-1) - 2/(x+1) = 2/x(^2) -1

    Could someone please tell me how you solve that?
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  2. #2
    A riddle wrapped in an enigma
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    Quote Originally Posted by JQ2009 View Post
    3/(x-1) - 2/(x+1) = 2/x(^2) -1

    Could someone please tell me how you solve that?
    Hi JQ2009,

    \frac{3}{x-1}-\frac{2}{x+1}=\frac{2}{x^2-1}

    \frac{3}{x-1}-\frac{2}{x+1}=\frac{2}{(x-1)(x+1)}

    Now, multiply each term by (x-1)(x+1) and continue from there.
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  3. #3
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    Thanks but I am still confused.

    I know that leaves you with 2 on the right hand side but what happens to the left?
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  4. #4
    A riddle wrapped in an enigma
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    Quote Originally Posted by masters View Post
    Hi JQ2009,

    \frac{3}{x-1}-\frac{2}{x+1}=\frac{2}{x^2-1}

    \frac{3}{x-1}-\frac{2}{x+1}=\frac{2}{(x-1)(x+1)}

    Now, multiply each term by (x-1)(x+1) and continue from there.
    Quote Originally Posted by JQ2009 View Post
    Thanks but I am still confused.

    I know that leaves you with 2 on the right hand side but what happens to the left?
    (x-1)(x+1)\left(\frac{3}{(x-1}\right)-(x-1)(x+1)\left(\frac{2}{x+1}\right)=(x-1)(x+1)\left(\frac{2}{(x-1)(x+1)}\right)

    3(x+1)-2(x-1)=2
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