Thread: limits #1 ...urgent

find the limits:

1.f(x)=sqrt(x^2+4x+3) -(x+2) when x goes to +infinity
2. f(x)=[sqrt(x+6) - 3]/ (x-3) x=3

any help is appreciated. thanx

1. multiply top and bottom by ( ) then let xgo to infinity

yeah, i've tried that and f(x)=1/ sqrt(x^2+4x+3) + x+2 and it's still an indertiminate form

sorry for the bad english

Originally Posted by blertta

yeah, i've tried that and f(x)=1/ sqrt(x^2+4x+3) + x+2 and it's still an indertiminate form

sorry for the bad english

yes thats right so when x goes to infinity sqrt(x^2+4x+3) + x+2 goes to infinity
so you get 1/h h goes to infinity and this limit is zero

try to write the equations properly so that we know what is being divided.

you can do the same thing to 2 aswell.