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Math Help - limits #1 ...urgent

  1. #1
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    limits #1 ...urgent

    find the limits:

    1.f(x)=sqrt(x^2+4x+3) -(x+2) when x goes to +infinity
    2. f(x)=[sqrt(x+6) - 3]/ (x-3) x=3

    any help is appreciated. thanx
    Last edited by mr fantastic; October 5th 2009 at 05:50 PM. Reason: Moved from another thread
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  2. #2
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    1. multiply top and bottom by ( \sqrt{x^2+4x+3}+(x+2)) then let xgo to infinity
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  3. #3
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    yeah, i've tried that and f(x)=1/ sqrt(x^2+4x+3) + x+2 and it's still an indertiminate form

    sorry for the bad english
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  4. #4
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    Quote Originally Posted by blertta View Post
    yeah, i've tried that and f(x)=1/ sqrt(x^2+4x+3) + x+2 and it's still an indertiminate form

    sorry for the bad english
    yes thats right so when x goes to infinity sqrt(x^2+4x+3) + x+2 goes to infinity
    so you get 1/h h goes to infinity and this limit is zero

    try to write the equations properly so that we know what is being divided.

    you can do the same thing to 2 aswell.
    Last edited by mr fantastic; October 5th 2009 at 05:51 PM. Reason: Merged posts and edited
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