How would you solve this equation 10x^(2/3)+4x^(1/3)-48=0 duno how to set fraction power with the math thing on this website. answer should be x=8 or -13.824 please show step by step method! many thanks!
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Let $\displaystyle u = x^{\frac{1}{3}}$ $\displaystyle 10u^2+4u-48 = 0$ Can you solve the quadratic
oh my days, my stupid moment always come. many thanks!
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