How would you solve this equation

10x^(2/3)+4x^(1/3)-48=0

duno how to set fraction power with the math thing on this website.

answer should be x=8 or -13.824

please show step by step method!

many thanks!

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- Oct 5th 2009, 10:39 AMBabyMiloHow to solve this when it's power of a fraction
How would you solve this equation

10x^(2/3)+4x^(1/3)-48=0

duno how to set fraction power with the math thing on this website.

answer should be x=8 or -13.824

please show step by step method!

many thanks! - Oct 5th 2009, 10:45 AMe^(i*pi)
Let $\displaystyle u = x^{\frac{1}{3}}$

$\displaystyle 10u^2+4u-48 = 0$

Can you solve the quadratic - Oct 5th 2009, 10:53 AMBabyMilo
oh my days, my stupid moment always come.

many thanks!