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Math Help - Sequential Proof

  1. #1
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    Sequential Proof

    Prove that the (2n+1)th term of the sequence U_n=n^{2}-1 is a multiple of 4.

    How do I do this?
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  2. #2
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    U_{2n+1}=(2n+1)^2-1=4n^2+4n+1-1=4(n^2+n) So it is a multiple of 4.
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  3. #3
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    EDIT: Nevermind, I just realised what a fool I'm being. I'll try it again soon.
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  4. #4
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    Quote Originally Posted by Viral View Post
    U_{2n+1}=(2n+1)^2-1=4n^2+1-1

    That's what I keep getting =\ .
    The expansion of (2n+1)^2 should be

    (2n+1)^2 = 4n^2+4n+1
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