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Thread: Fraction problems

  1. #1
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    Fraction problems

    Hey i was looking for help on these problems; how would i go about finding the solutions to them both?

    1.If a storage tank is holding 450 liters when it is three quarters full, how much will it contain when it is two thirds full?.

    And

    2.three people P,Q and R contribute to a fund. P provides 3/5 of the total, Q provides 2/3 of the remainder and R provides 8. determine a) the total of the fund. b)the contributions of P and Q.

    Thanks
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  2. #2
    Nrt
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    1)

    Let the total capacity of the tank be $\displaystyle x$.

    When it's $\displaystyle \frac{3}{4}$ full it can contain 450 liters.

    Now lets find its total capacity. If $\displaystyle \frac{3x}{4}=450$ then $\displaystyle x=\frac{4.450}{3}=600$

    So when it's $\displaystyle \frac{2}{3}$ full, there will be $\displaystyle \frac{2.600}{3}=400$ liters.
    Last edited by Nrt; Oct 4th 2009 at 05:03 AM.
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  3. #3
    Nrt
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    2)

    $\displaystyle Total=x$

    P provies $\displaystyle \frac{3}{5}$ of total which is $\displaystyle \frac{3x}{5}$, now the remaining is $\displaystyle x-\frac{3x}{5}=\frac{2x}{5}$.

    Q provides $\displaystyle \frac{2}{3}$ of the remainder, so $\displaystyle \frac{2x}{5}.\frac{2}{3}=\frac{4x}{15}$ that is the amount Q gives.

    R gives 8, it's equal to $\displaystyle \frac{2x}{15}$.

    ($\displaystyle \frac{2x}{5}-\frac{4x}{15}=\frac{2x}{15}$)

    I substracted the amount Q provided ($\displaystyle \frac{4x}{15}$) from the total fund left ($\displaystyle \frac{2x}{5}$) after P's contribution.

    So we know that 8$\displaystyle =\frac{2}{15}$ of the total amount. $\displaystyle 8.\frac{15}{2}=$60 is the total amount.

    From here we can find P's contribution which is $\displaystyle 60.\frac{3}{5}=$36 and Q's, $\displaystyle 60.\frac{4}{15}=$16
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  4. #4
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    Thanks mate, that made a lot more sense then the way i was going about it.
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