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Math Help - Algebra Subtraction

  1. #1
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    Algebra Subtraction

    Subtract 1 / 2[12y^2 + 1 / 4x(16x-8y)] from 12y^2 + 7xy + 5x^2

    And this is how I done it...

    12y^2 + 7xy + 5x^2 - 1/2[12y^2 - 1/4x(16x + 8y)]
    = 12y^2 + 7xy + 5x^2 - 6y^2 - 2y + 2xy
    = 6y^2 + 8xy + 5x^2 - 2x

    However, it turns out wrong. If you could point out my mistake while solving this sum, I would appreciate your kindness. Thank you!
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  2. #2
    Member SENTINEL4's Avatar
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    12y^2+7xy+5x^2-\frac{1}{2}(12y^2+\frac{1}{4x}(16x-8y)) = 12y^2+7xy+5x^2-\frac{1}{2}12y^2-\frac{1}{2}\frac{1}{4x}(16x-8y) =

    = 12y^2+7xy+5x^2-6y^2-\frac{1}{8x}(16x-8y) = 12y^2+7xy+5x^2-6y^2-2+\frac{y}{x}

    This is gonna be without the parentheses
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  3. #3
    Member SENTINEL4's Avatar
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    Quote Originally Posted by DengXiang View Post
    12y^2 + 7xy + 5x^2 - 1/2[12y^2 - 1/4x(16x + 8y)]
    This is wrong... The right is 12y^2+7xy+5x^2-1/2[12y^2+1/4x(16x-8y)]
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