log x + log (x-17) = log (14x) so from what i have learned so far.. i would say x2-17x=14x but that seems bizarre, no?
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Originally Posted by badshahkhan log x + log (x-17) = log (14x) so from what i have learned so far.. i would say x2-17x=14x but that seems bizarre, no? Correct (and I'm not wrong this time). x^2 - 17x = 14x => x^2 - 31x = 0 => x(x - 31) = 0. Therefore x = 0 (rejected because log 0 is not defined) or x = 31 (accepted).
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