if the graph of a function of y=log_a (x) goes through (22,1) then what does a =?
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Originally Posted by badshahkhan if the graph of a function of y=log_a (x) goes through (22,1) then what does a =? Solve $\displaystyle 1 = \log_a (22)$ for $\displaystyle a$. Here is the first and last step: $\displaystyle a^1 = 22$.
Originally Posted by badshahkhan if the graph of a function of y=log_a (x) goes through (22,1) then what does a =? change $\displaystyle y = \log_a(x)$ to an exponential equation ... then sub in the given values.
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