# Math Help - I can't figure out this log problem!!!!

1. ## I can't figure out this log problem!!!!

what would the x be? i am so confused...

2. $\log_2x+ \log_2(x+3) = \log_28$

addition of logs gives

$\log_2(x(x+3)) = \log_28$

$\log_2(x^2+3x) = \log_28$

raising both sides to the power of 2

$x^2+3x = 8$

$x^2+3x - 8=0$

now we have a quadratic, do you know how to solve this?

3. yes ofcourse! 1.7 i believe

4. Originally Posted by badshahkhan
yes ofcourse! 1.7 i believe
If an answer correct to 1 decimal place is required then this is correct. But if an exact answer is required then it's not correct.